Triangles (Class 9, Math) / Quiz / By gyanpur Please enter your email: 1. In given figure, the measure of ∠BAC is (a) 60° (b) 50° (c) 70° (d) 80° 2. In figure if AE || DC and AB = AC, find the value of ∠ABD. (a) 130° (b) 110° (c) 120° (d) 70° 3. In figure X is a point in the interior of square ABCD, AXYZ is also a square. If DY = 3 cm and AZ = 2 cm, then find BY. (a) 5 cm (b) 6 cm (c) 7 cm (d) 8 cm 4. In figure AB ⊥ AE, BC ⊥ AB, CE = DE and ∠AED = 120°, then find ∠ECD. (a) 80° (b) 70° (c) 85° (d) 60° 5. In ΔABC, ∠C = ∠A and BC = 4 cm and AC = 5 cm, then find length of AB. (a) 5 cm (b) 3 cm (c) 4 cm (d) 2.5 cm 6. In ΔABC, AB = AC and ∠B = 50°, then find ∠C. (a) 50° (b) 40° (c) 80° (d) 120° 7. In figure, D is the mid-point of side BC of a ΔABC and ∠ABD = 50°. If AD = BD = CD, then find the measure of ∠ACD. (a) 30° (b) 70° (c) 80° (d) 40° 8. In figure, ABC is an isosceles triangle whose side AC is produce to E and through C, CD is drawn parallel to BA. Find the value of x. (a) 52° (b) 156° (c) 76° (d) 104° 9. In figure AB ⊥ BE and EF ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to (a) ΔEFC (b) ΔECF (c) ΔDEF (d) ΔFEC 10. D is a point on the side BC of a ΔABC such that AD bisects ∠BAC. Then (a) BD = CD (b) BA > BD (c) BD > BA (d) CD > CA 11. It is given that ΔABC = ΔFDE and AB = 5 cm, ∠B = 40° and ∠A = 80°. Then which of the following is true? (а) DF = 5 cm, ∠F = 60° (b) DF = 5 cm, ∠E = 60° (c) DE = 5 cm, ∠E = 60° (d) DE = 5 cm, ∠D = 40° 12. Two sides of a triangle are of lengths 5 cm and 1.5 cm. The length of the third side of the triangle cannot be (a) 3.6 cm (b) 4.1 cm (c) 3.8 cm (d) 3.4 cm 13. In ΔPQR, if ∠R > ∠Q, then (a) QR > PR (b) PQ > PR (c) PQ < PR (d) QR < PR 14. In triangles ABC and PQR, AB = AC, ∠C = ∠P and ∠B = ∠Q. The two triangles are (a) isosceles but not congruent (b) isosceles and congruent (c) congruent but not isosceles (d) neither congruent nor isosceles 15. In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if (a) BC = EF (b) AC = DE (c) AC = EF (d) BC = DE Loading …